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Irrigation Pump

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In the figure above, a pump maintains a pressure of $P = 2.5$ atm. (1 atm = $10^5$ Pascals) on top of a tank of water with a cross sectional area $A = 10$ m$^2$. An irrigation pipe at the bottom leads up a slope to a farmer's field. The vertical distance between the top surface of water in the tank and the opening of the pipe is $H = 10$ m. The cross-sectional area of the pipe is $a = 4$ cm$^2$. The top pipe is open to air pressure $P_0 = 1$ atm. Recall that the density of water is $\rho = 10^3$ kg/m$^3$.

a) What is the velocity of the water coming from the pipe?

b) Is the pressure at the bottom of the tank greater inside the main vessel (point 1 on figure above) or inside the pipe (point 2)? Briefly explain.



Robert G. Brown 2000-12-09